mirror of
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58 lines
2.3 KiB
Plaintext
58 lines
2.3 KiB
Plaintext
<%
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// TODO: code cleanup + putting this behind a toggle/attribute
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const previousNote = (() => {
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// If we are at the subRoot, there is no previous
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if (note.noteId === subRoot.note.noteId) return null;
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const parent = note.getParentNotes()[0];
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const children = parent.getChildNotes();
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const index = children.findIndex(n => n.noteId === note.noteId);
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// If we are the first child, previous goes up a level
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// this is already protected by the first if statement
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if (index === 0) return parent;
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// We are not the first child at this level so previous
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// should go to the end of the previous tree
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let candidate = children[index - 1];
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while (candidate.hasChildren()) {
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const children = candidate.getChildNotes();
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const lastChild = children[children.length - 1];
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candidate = lastChild;
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}
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return candidate;
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})();
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const nextNote = (() => {
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// If this currently active note has children, next
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// should be the first child
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if (note.hasChildren()) return note.getChildNotes()[0];
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let parent = note.getParentNotes()[0];
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let children = parent.getChildNotes();
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let index = children.findIndex(n => n.noteId === note.noteId);
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// If we are not the last of the current level, just go
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// to the next sibling note
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if (index !== children.length - 1) return children[index + 1];
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// We are the last sibling, we need to find the next ancestral note
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while (index === children.length - 1) {
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// If we are already at subRoot level, no reason trying to go higher
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if (parent.noteId === subRoot.note.noteId) return null;
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const originalParent = parent;
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parent = parent.getParentNotes()[0];
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children = parent.getChildNotes();
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index = children.findIndex(n => n.noteId === originalParent.noteId);
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}
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return children[index + 1];
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})();
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%>
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<div class="navigation">
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<% if (previousNote) { %><a class="previous" href="./<%- previousNote.shareId %>"><%- previousNote.title %></a><% } %>
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<% if (nextNote) { %><a class="next" href="./<%- nextNote.shareId %>"><%- nextNote.title %></a><% } %>
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</div> |