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refactor(search): simplify null check and use join for text concatenation
根据代码审查建议优化代码:
- 移除多余的 `elements &&` 检查,因为 Array.isArray() 本身可处理 null/undefined
- 使用 `join(" ")` 替代 `toString()` 以确保文本元素用空格分隔,更适合全文搜索
- 移除显式类型声明,让 TypeScript 自动推断
🤖 Generated with [Claude Code](https://claude.com/claude-code)
Co-Authored-By: Claude Opus 4.5 <noreply@anthropic.com>
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@ -315,15 +315,15 @@ class NoteContentFulltextExp extends Expression {
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[key: string]: any; // Other properties that may exist
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[key: string]: any; // Other properties that may exist
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}
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}
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let canvasContent = JSON.parse(content);
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const canvasContent = JSON.parse(content);
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const elements: Element[] = canvasContent.elements;
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const elements = canvasContent.elements;
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if (elements && Array.isArray(elements)) {
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if (Array.isArray(elements)) {
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const texts = elements
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const texts = elements
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.filter((element: Element) => element.type === "text" && element.text) // Filter for 'text' type elements with a 'text' property
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.filter((element: Element) => element.type === "text" && element.text) // Filter for 'text' type elements with a 'text' property
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.map((element: Element) => element.text!); // Use `!` to assert `text` is defined after filtering
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.map((element: Element) => element.text!); // Use `!` to assert `text` is defined after filtering
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content = normalize(texts.toString());
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content = normalize(texts.join(" "));
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} else {
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} else {
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content = "";
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content = "";
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}
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}
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